\newproblem{lay:2_1_10}{
  % Problem identification
	\begin{large}
	  \hspace{\fill}\newline
    \textbf{Lay, 2.1.10}
	\end{large}
	\\
  \ifthenelse{\boolean{identifyAuthor}}{\textit{Carlos Oscar Sorzano, Aug. 31st, 2013} \\}{}

  % Problem statement
  Let $A=\begin{pmatrix}3 & -6 \\ -1 & 2\end{pmatrix}$, $B=\begin{pmatrix}-1 & 1 \\ 3 & 4\end{pmatrix}$ and $C=\begin{pmatrix}-3 & -5 \\ 2 & 1\end{pmatrix}$.
	Verify that $AB=AC$ and yet $B\neq C$.
}{
   % Solution
	
	\begin{center}
	   $AB=\begin{pmatrix}3 & -6 \\ -1 & 2\end{pmatrix}\begin{pmatrix}-1 & 1 \\ 3 & 4\end{pmatrix}=\begin{pmatrix}-21 & -21 \\ 7 & 7\end{pmatrix}=
		   \begin{pmatrix}3 & -6 \\ -1 & 2\end{pmatrix}\begin{pmatrix}-3 & -5 \\ 2 & 1\end{pmatrix}=AC$
	\end{center}
}
\useproblem{lay:2_1_10}
\ifthenelse{\boolean{eachProblemInOnePage}}{\newpage}{}
